There are two solutions in one image-charge problem?

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SUMMARY

The discussion revolves around a problem involving two different solutions to a physics question related to work calculation, attributed to Griffiths and a lecturer. The inconsistency between these solutions raises questions about which approach is correct. Griffiths provides an alternative method to calculate work by integrating force over a specified path, suggesting simplification by setting parameters equal. The conversation emphasizes the need for clarity in educational resources.

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  • Understanding of classical mechanics principles, particularly work and force.
  • Familiarity with integration techniques in calculus.
  • Knowledge of problem-solving strategies in physics.
  • Ability to analyze and compare different mathematical approaches.
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  • Review Griffiths' method for calculating work in physics problems.
  • Study integration of force over a path in classical mechanics.
  • Examine common discrepancies in educational materials and their resolutions.
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Students studying physics, educators seeking clarity in teaching methods, and anyone interested in resolving inconsistencies in academic problem-solving approaches.

garylau
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Sorry
there are two different solutions in one question
! which one is correct??
the first one is written by griffiths

the second one is written by a lecturer.

they are not consistent in the same question
So which one is correct?
thank you
 

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Well, in the preceding section Griffiths gives an alternative way to calculate the work !
It's not too complicated to integrate the force you calculated over the path bx = ay from ##\infty## to ##(a,b)## .
(And you can simplify by setting ##a=b## -- all you're after is factor of 2).

This thread should be in the homework forum.
 
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BvU said:
This thread should be in the homework forum.
It looks more like a studying question so far, so we can leave it here for now.
 

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