Recently, I used the metric for the traversable wormhole (the one in this link): http://www.spacetimetravel.org/wurmlochflug/wurmlochflug.html ds2= -c2dt2 + dl2 + (b2 + l2)(dΘ2 + sin2(Θ)dΦ2) I derived the metric tensor from this space-time interval and then from there, I derived the Christoffel symbols, the Ricci tensor, the curvature scalar, and ultimately the Einstein tensor. Here was my Einstein tensor: G00=(-b2c2)/(b2 + l2)2 G11=(-b2)/(b2 + l2)2 G22=(b2)/(b2 + l2) G33=(b2sin2(Θ))/(b2 + l2) Every other element was 0. I then multiplied this Einstein tensor by (c4)/(8πG) in order to derive my stress energy momentum tensor. I did this because the equations (without the cosmological constant) are: Rμν - (1/2) gμνR =[ (8πG)/(c4)]Tμν Here was the stress energy momentum tensor that I derived: T00 = (-b2c6)/(8πG)(b2 + l2)2 T11 = (-b2c4)/(8πG)(b2 + l2)2 T22 = (b2c4)/(8πG)(b2 + l2) T33 = (b2c4sin2(Θ))/(8πG)(b2 + l2) Every other element was 0. Now here is where the problem comes in. I used SI units and did some dimensional analysis on the terms of the stress energy momentum tensor to see if their ultimate dimensions would come out to be the dimensions of whatever quantity they represent (such as energy density in the case of T00). It turned out that most of the dimensions did not come out to represent the right quantities. For example: T00 = (-b2c6)/(8πG)(b2 + l2)2 Now considering that b is the radius of the throat of the wormhole, its unit would be meters. l is the radial coordinate (or so I am told). Therefore, its unit is meters. c is m/s of course. G= m3/ (kg * s2 ) You can do dimensional analysis on Newton's gravitational force equation to derive the units of G. Now, the units for T00 would turn into: (m8/s6) / (m7/(kg * s2)) = (m * kg) / s4 Those are not the units for energy density. The units for energy density are: (kg* m2)/s2 These units can be derived by doing dimensional analysis on common energy formulas such as kinetic energy, gravitational potential energy, or Einstein's famous E= mc2. The case of incorrect units is the case with most of the other elements as well. This leads me to the following possible alternative conclusions: 1. When you plug a metric into the Einstein field equations and derive the Einstein tensor, you don't actually multiply it by (c4)/(8πG) to get the stress energy momentum tensor. Instead, you just set the stress energy momentum tensor to any one of your choosing (whether it be the electromagnetic stress energy momentum tensor, dust, vaccum, etc...) and then just set each element of your Einstein tensor equal to (8πG)/(c4) multiplied by the corresponding element of the stress energy momentum tensor of your choosing. You then just solve for whatever variables need to be solved for. In other words, if I wanted to use the electromagnetic stress energy momentum tensor, then I would have just set my: T00 = (-b2c6)/(8πG)(b2 + l2)2 equal to: (8πG)/(c4) times the T00 of the electromagnetic stress energy momentum tensor which equals: (1/2)ε0E2 + (1/2) (B2/μ0) Conclusion #2: l is not the radial coordinate after all. It is something else. Conclusion # 3: I made some calculation errors (which I don't think I did and I hope that I didn't because these calculations took a long time). Conclusion #4: There should be a cosmological constant involved in this scenario. Can somebody please tell me which of these conclusions (if any) is correct? If conclusion # 2 is the correct one, then can somebody please tell me what l is? If it is #4, then can you please tell me how to determine what the cosmological constant is?