Thermal Conduction and Newton's Law of Cooling

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SUMMARY

This discussion centers on the compatibility of Fourier's law of thermal conduction and Newton's law of cooling. Fourier's law, expressed as \(\mathbf{j}=-k\nabla T\), predicts an infinite rate of cooling at temperature discontinuities, while Newton's law effectively manages these scenarios without divergence. The conversation highlights that while Fourier's law may suggest an instantaneous infinite cooling rate, this phenomenon is transient and resolves over time, with heat transfer proportional to time to the 1/2 power. The transient heat conduction equation can be solved using a similarity solution to clarify this behavior.

PREREQUISITES
  • Understanding of Fourier's law of thermal conduction
  • Familiarity with Newton's law of cooling
  • Basic knowledge of heat transfer concepts
  • Ability to solve differential equations related to heat conduction
NEXT STEPS
  • Study the transient heat conduction equation and its solutions
  • Explore similarity solutions in heat transfer analysis
  • Investigate the implications of temperature discontinuities in thermal systems
  • Learn about boundary layer theory in thermal conduction
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Physicists, engineers, and students studying thermodynamics and heat transfer, particularly those interested in the interplay between conduction laws and cooling processes.

dEdt
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Fourier's law of thermal conduction states that \mathbf{j}=-k\nabla T, where \mathbf{j} is the heat flux. Integrating both sides of this equation over a closed surface gives the equation \frac{dQ}{dt}=-k\int \nabla T \cdot d\mathbf A.

If there is a temperature discontinuity across this surface, then \frac{dQ}{dt} diverges, in contradiction with Newton's law of cooling. Are Fourier's law of conduction and Newton's law of cooling mutually incompatible?
 
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dEdt said:
Fourier's law of thermal conduction states that \mathbf{j}=-k\nabla T, where \mathbf{j} is the heat flux. Integrating both sides of this equation over a closed surface gives the equation \frac{dQ}{dt}=-k\int \nabla T \cdot d\mathbf A.

If there is a temperature discontinuity across this surface, then \frac{dQ}{dt} diverges, in contradiction with Newton's law of cooling. Are Fourier's law of conduction and Newton's law of cooling mutually incompatible?
What makes you think there can be a temperature discontinuity at the surface? There, of course, can be a discontinuity of the temperature gradient at the surface, but this equation applies inside the region bounded by the surface.

Chet
 
Chestermiller said:
What makes you think there can be a temperature discontinuity at the surface? There, of course, can be a discontinuity of the temperature gradient at the surface, but this equation applies inside the region bounded by the surface.

Chet

Well, let's imagine that you put a warm bottle of beer in a refrigerator to cool it down. At the surface of the bottle there is (at least initially) a temperature discontinuity, because the beer and the air in the fridge are at different temperatures. Newton's law of cooling has no trouble handling this, but Fourier predicts (at least initially) an infinite rate of cooling.
 
dEdt said:
Newton's law of cooling has no trouble handling this, but Fourier predicts (at least initially) an infinite rate of cooling.

It predicts an infinite rate of cooling of the infinitesimally thin layer of the can that is in contact with the cold air, which is probably approximately right.
 
dEdt said:
Well, let's imagine that you put a warm bottle of beer in a refrigerator to cool it down. At the surface of the bottle there is (at least initially) a temperature discontinuity, because the beer and the air in the fridge are at different temperatures. Newton's law of cooling has no trouble handling this, but Fourier predicts (at least initially) an infinite rate of cooling.
Yes, this is true, but it only lasts an instant. And the cumulative amount of heat transferred at short times will be proportional to time to the 1/2 power. One can determine this by solving the transient heat conduction equation in the region near the boundary using a similarity solution (i.e. Boundary layer solution).

Chet
 

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