1. The problem statement, all variables and given/known data A geodesic dome constructed with an aluminum framework is a nearly perfect hemisphere; its diameter measures 55.0 on a winter day at a temperature of -18 C. How much more interior space does the dome have in the summer, when the temperature is 30? 2. Relevant equations Linear Expansion: delta L=alpha(L_original)(delta T) Volume Expansion: delta V=(3)alpha(V_original)(delta T) 3. The attempt at a solution Ok so I for this question I treated it as a sphere and halved my answer because I though it made sense, not sure if it really mattered First attempt: I calculated the original volume of the sphere, which is 47713 m^3. And then I used the volume expansion to calculate the increase in the volume of the sphere which was delta V=3(2.4*10^-5)(48)(47713) = 164.9L and divide this by 2 and you get 82.4L But this is wrong Second attempt: I tried linear expansion, this way makes near to no sense so I'll abreviate it, I used the linear expansion formula to calculate directly the increase in the radius, and then from there calculated the increase in volume, didnt work Third attempt: I thought I had it this time Firsty I calculated the surface area of the sphere = 6361.73 Then calculated the area increase which is delta A=(48)(6361.73)(2)(2.4*10^-5) = 14.66m^2878.53 The calculated the new area =6376.39 Then the new radius, sqrt(6376.39/4Pi) = 22.526 So the new volume of the sphere= 47878.53. Original volume= 47712.93.....47878.53-47712.93 =165.6 for a sphere Volume increase for hemispere= 82.8 m^3 Is this right? Because I'm using masteringphysics and I said 82.5 by mistake and it didnt say I was even close to the answer, I only have one attempt to get this right so I dont want to get it wrong. Thanks very much for the help, sorry if its a bit convoluted, my first time posting.