Thermal expansion of a pendulum

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Homework Help Overview

The discussion revolves around the thermal expansion of a steel pendulum and its impact on timekeeping accuracy. The original poster is tasked with determining the maximum temperature variation that the pendulum can withstand without delaying more than one second per day.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to relate the pendulum's period to temperature changes and calculates the necessary adjustments based on the coefficient of thermal expansion. Some participants question the correctness of the calculations and the application of relevant equations.

Discussion Status

The discussion includes attempts to verify calculations and clarify the coefficient of thermal expansion for steel. Participants are exploring different interpretations of the problem and checking assumptions about the equations used.

Contextual Notes

There is mention of conflicting information regarding the coefficient of thermal expansion, which has led to adjustments in the original calculations. The original poster also notes a correction in their understanding of the coefficient's application.

fluidistic
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Hi,
I've done the problem but I'm unsure of my answer. I would be glad if you could check it out.

Homework Statement


A steal pendulum is considered a clock at a certain temperature.
What is the maximum variation of temperature we can submit to the pendulum if it cannot delay more than one second by day?



Homework Equations

Coefficient of dilation of steal : [tex]11\times 10 ^{-6}°C^{-1}[/tex].



The Attempt at a Solution


First I notice that a period of the pendulum corresponds to a second. Then I calculated the number of seconds in day to be 86400.
Say it delays 1 second in a day and I want to calculate its period. We have that [tex]86400T=86401T'[/tex]. Replacing [tex]T[/tex] with [tex]2\pi \sqrt {\frac{g}{l}}[/tex] then I get that [tex]l'=0.9999768523l[/tex] where [tex]l[/tex] is the length of the pendulum and [tex]l'[/tex] the length of the heated pendulum.
Now I want to find the length it cannot overpass : [tex]l(1-0.9999768523)=0.00002314774628l[/tex].
Looking at the coefficient of dilation of steal, if I heat the pendulum by 1°C, it will grow [tex]0.0000011l[/tex]. From it, I just look and see that I can heat the pendulum up to 23°C more than it is.
To my intuition it looks too much. What do you say?
 
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LaTeX Code: 0.0000011l
Is this correct?
 
According to my assignments yes. However I just checked it up on wikipedia thanks to you. (the page is http://en.wikipedia.org/wiki/Coefficient_of_dilatation) and they give a range of [tex]33.0[/tex] ~ [tex]39.0 \times 10 ^{-6}[/tex]. This reduce the temperature I got by 3. So it's around 7°C which makes more sense to me.
EDIT: Ah no! Sorry, it is what my assignment says, around [tex]11\times 10 ^{-6}°C^{-1}[/tex] since we're talking about the coefficient of linear thermal expansion...
 
Does the equation [itex]\delta l=L \alpha T[/itex] not apply here? Well that is what I thought to use first when you found the extension.
 
Ah I made a little mistake! The coefficient of dilation of steel is [tex]11 \times 10 ^{-6}°C^{-1}[/tex].
Quoting myself :
Looking at the coefficient of dilation of steal, if I heat the pendulum by 1°C, it will grow 0.0000011l .
should be
Looking at the coefficient of dilation of steal, if I heat the pendulum by 1°C, it will grow 0.000011l
. With this, the answer becomes 2.3 °C which is the right answer. (I asked the professor).
I'm glad I found my mistake.
 

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