Thermal expansion of water and a bubble

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SUMMARY

The discussion centers on calculating the volume of a bubble exhaled by a scuba diver at a depth of 17.4 meters in a lake, where the initial water temperature is 8.25°C and the surface temperature is 15.1°C. The diver exhales a bubble with an initial volume of 23.6 cm³. Key insights reveal that the pressure difference between the bubble at depth and at the surface significantly influences its volume, overshadowing the effects of thermal expansion of water. The relevant equation for this scenario is ΔV/V = βΔT, but the primary focus should be on the pressure changes as the bubble ascends.

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  • Understanding of the Ideal Gas Law
  • Knowledge of pressure dynamics in fluids
  • Familiarity with thermal expansion concepts
  • Basic algebra for volume calculations
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  • Study the Ideal Gas Law and its applications in scuba diving scenarios
  • Research pressure changes in fluids and their effects on gas volumes
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nickb145
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Homework Statement

A scuba diver is 17.4m below the surface of the lake, where the water temperature is 8.25∘C. The density of fresh water is 1000 kg/m3. The diver exhales a 23.6cm3 bubble.What's the bubble's volume as it reaches the surface, where the water temperature is 15.1∘C?

Homework Equations



ΔV/V=βΔTI think that is the only equation needed

The Attempt at a Solution



I would think that i could find ΔV and then plug everything else in but how to i convert the density to cm3? I think once i figured that out id be able to do it.
 
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Are you sure you have not omitted some other details of the problem?

Thermal expansion of water is almost completely irrelevant here. When the bubble is produced, the pressure in the bubble is almost three times atmospheric, while at the surface it is just atmospheric. That alone will have a much greater impact on the volume than the tiny change of density of water.
 
Could this be an ideal gas law question?
 

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