Thermal Expansion on Pendum- Period related question

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joeyscl
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Homework Statement



A grandfather clock is calibrated to 20 degrees Celsius. If the room temperature were to be increased to and maintained at 30 degrees, how much would the clock run slower by in a 7 day period? (Yes, the length of the pendulum is NOT given)

Can someone help me with this question please? Also wondering, if you're going to do this question with calculus, is there a way to not use calculus and solve it?


Homework Equations



delta T brass= L(initial)x 1.9x10^-5 x 10
period P= 2Pi x Root (L/g)


The Attempt at a Solution


I am completely stumped by this question, all i know is dL/L= 1.9x10^-4
 
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joeyscl said:

Homework Statement



A grandfather clock is calibrated to 20 degrees Celsius. If the room temperature were to be increased to and maintained at 30 degrees, how much would the clock run slower by in a 7 day period? (Yes, the length of the pendulum is NOT given)

Can someone help me with this question please? Also wondering, if you're going to do this question with calculus, is there a way to not use calculus and solve it?


Homework Equations



delta T brass= L(initial)x 1.9x10^-5 x 10
period P= 2Pi x Root (L/g)


The Attempt at a Solution


I am completely stumped by this question, all i know is dL/L= 1.9x10^-4

shouldn't there be an equation relating dL and dt ?
 
erm, well, it gives you Period, it also gives u % change in length (well, more like u can calculate it)... how do u go from there?
 
This is a classic problem that needs binomial expansion.

P+dP = 2*pi * sqrt((L+dL)/g)

Expand out the sqrt as a binomial expansion, to first order, then subtract off P to get the value for dP.
 
except you're not given L and dL...
you can only calculate dL/L
 
cmon, if it were THAT easy i wouldn't be asking for help >,<
I was *easily* one of the best physics students in my Grade in my high school days (only last year, haha) >,<
 
Do you even remember how to do a binomial expansion...? I think you'll find that it just works... Any a word of advice: no matter how good you think you are, you're still here asking questions -- questions that some of the advisers will have been doing without every asking anyone else since long before you were born.
 
genneth si right.
You shold use binomal expansion. The other way of doing it, is to write log of the equation [tex]P = 2\pi\sqrt{L/g}[/tex] and then derivate it. What you'll get is
[tex]\frac{\Delta P}{P}=\frac{1}{2}\frac{\Delta L} {L}[/tex]