[Thermo] - Maxwells Relations? Prove the Validity of the Equations

  • Thread starter Thread starter tesla22
  • Start date Start date
  • Tags Tags
    Relations Thermo
Click For Summary
SUMMARY

The discussion centers on proving the validity of Maxwell's relations in thermodynamics, specifically focusing on three equations involving partial derivatives of thermodynamic potentials. The equations discussed are: (1) (d²f/dv²)_T = 1/Kv, (2) (d²h/ds²)_P = T/Cp, and (3) (d²u/ds²)_v = T/Cv. The participants clarify the relationships between temperature, entropy, and specific heat capacities, ultimately leading to a solution for the second and third equations while identifying a mistake in the first equation's formulation.

PREREQUISITES
  • Understanding of Maxwell's relations in thermodynamics
  • Familiarity with partial derivatives and their applications in thermodynamic equations
  • Knowledge of thermodynamic potentials such as Helmholtz free energy (F), enthalpy (H), and internal energy (U)
  • Concepts of isothermal compressibility (K), heat capacities (Cp and Cv), and their definitions
NEXT STEPS
  • Study the derivation of Maxwell's relations and their implications in thermodynamics
  • Learn about the differential forms of thermodynamic potentials and their derivatives
  • Explore the relationship between entropy and temperature in detail
  • Investigate the applications of isothermal compressibility in real-world thermodynamic systems
USEFUL FOR

Students and professionals in thermodynamics, particularly those studying or working in fields related to physical chemistry, engineering, and materials science, will benefit from this discussion.

tesla22
Messages
3
Reaction score
0

Homework Statement

We are working on some problems for class and we are given statements which I accept as valid but don't know how to prove they are valid. I believe I have to utilize the maxwell relations but the terms seem unfamiliar to me.

Homework Equations



(1)
Partial
(d^2f / ds^2)_T = T / Kv

(2)
Partial
(d^2h / ds^2)_P = T / C_p

(3)
Partial
(d^2u / ds^2)_v = T / C_v

The Attempt at a Solution



For the first equation, I know that the isothermal compressibiity K = -1/v partial(dv/dP)_T

For the second equation I also know that C_p/T = partial(ds/dT)_P = 1/T * partial(dh/dT)_P and i need to take this knowledge to combine the equations but I don't see how I would be getting the square on the ds out of this. Obviously I'm missing something.

C_v/T should be the same proof with u in place of h holding v constant.

Thanks for any help.
 
Physics news on Phys.org
Last edited by a moderator:
Thank You, I think the answers were staring me in the face but in a different format and i didn't put 2 and 2 together until your response. I now have a solution where T=du/ds with v constant and T=dh/ds with p constant (correct?) and plugging these into the equations cv=T(ds/dt)_v and cp=T(dt/ds)_p to get the desired proof. I think its right.

I'm still struggling with the third one however so any assistance would be appreciated. How do you make the proper symbols appear?
 
The first relation can't be true, the units don't match up.
 
Mapes said:
The first relation can't be true, the units don't match up.

Yes that's the one I'm struggling with sorry, the first one. The 2nd and 3rd I believe I have proven as said in the previous post.

I completely screwed up the first one, the actual problem is as follows:

(d^2f / dv^2)_T = 1 / Kv

This is the one I am struggling with at the moment. Sorry I was trying too hard to convey the format of the problem that i got the variables wrong somehow.
 
OK, that makes a lot more sense. Try writing out the differential form of the Helmholtz free energy dF and taking the derivative of that twice with respect to V at constant T. The first derivative equals a well-known parameter.
 

Similar threads

Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
5
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
Replies
2
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K