You don't need to know what a diatomic gas is to solve this problem. They give you the value of the heat capacity. That's all you need.Diamond101 said:Homework Statement
A sample consisting of one mole of a diatomic perfect gas is heated from 25 °C to 200 °C at constant volume. Calculate q, w, ΔU and ΔH for the process, given that Cv = 23.02 J K-1 mol-1 .
Homework Equations
Im studying for mid terms and i have no lecture notes on diatomic gas looking online currently haven't found much. Please explain
The Attempt at a Solution
du=w-cvdt
cv=5/2nr
how do i find work , work it -pdv right? i wasnt given pressure or is it understood as 1 bar and i wasnt given a volumeChestermiller said:You don't need to know what a diatomic gas is to solve this problem. They give you the value of the heat capacity. That's all you need.
If the volume of gas is constant, how much work is done?
What is that Cv doing that equation that you wrote? The equation is incorrect. It should read ΔU=Q-W
If the volume doesn't change, what is dv equal to?Diamond101 said:how do i find work , work it -pdv right? i wasnt given pressure or is it understood as 1 bar and i wasnt given a volume
0, and because w=pdv no work is done ? is this an isochoric process? would du=n cvdtChestermiller said:If the volume doesn't change, what is dv equal to?
Very nice. Yes. isochoric is synonymous with constant volume. And your equation for the differential change in internal energy is correct.Diamond101 said:0, and because w=pdv no work is done ? is this an isochoric process? would du=n cvdt
thank you ever so muchChestermiller said:Very nice. Yes. isochoric is synonymous with constant volume. And your equation for the differential change in internal energy is correct.
Chet