Thermodyanmics, specific heat capacity

[Jennifer001]

Homework Statement

a 4kg iron hammer is initally 700 degree celsius is droppped into a bucket containing 20kg of water at 25degree celsius. what is the final temperture

Homework Equations

q=mc(delta)T

The Attempt at a Solution

m1=4kg
m2=20kg
T1=700=973K
T2=25=298
i know the system is in equilibrium but i don't know how to solve it correctly.. so here's my shot at it

Q=mc(delta)T
=(4)(449J/kgK)(Tf-973)=(20)(4190J/kgK)(Tf-298)

i think I'm doing this question wrong because .. when i solve for Tf i get a negative number of -288.66K

help?

 

[Jennifer001]

nvm forget this question i just figured out how to do it... i forgot to put the negative sign for the iron since it loses heat.