Thermodyanmics, specific heat capacity

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SUMMARY

The discussion revolves around a thermodynamics problem involving a 4 kg iron hammer at 700 degrees Celsius dropped into 20 kg of water at 25 degrees Celsius. The key equation used is q=mc(delta)T to determine the final temperature (Tf) of the system. The initial attempt to solve the equation resulted in an incorrect negative temperature due to the omission of the negative sign for the heat lost by the iron. The correct approach involves applying the principle of heat transfer and ensuring the heat lost by the hammer equals the heat gained by the water.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Familiarity with specific heat capacity (e.g., 449 J/kgK for iron, 4190 J/kgK for water)
  • Ability to manipulate algebraic equations
  • Knowledge of thermal equilibrium concepts
NEXT STEPS
  • Study the concept of thermal equilibrium in thermodynamics
  • Learn about specific heat capacity calculations for different materials
  • Explore the application of the first law of thermodynamics in heat transfer problems
  • Practice solving similar thermodynamics problems involving heat transfer
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone looking to improve their problem-solving skills in heat transfer scenarios.

Jennifer001
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Homework Statement



a 4kg iron hammer is initally 700 degree celsius is droppped into a bucket containing 20kg of water at 25degree celsius. what is the final temperture



Homework Equations



q=mc(delta)T

The Attempt at a Solution



m1=4kg
m2=20kg
T1=700=973K
T2=25=298
i know the system is in equilibrium but i don't know how to solve it correctly.. so here's my shot at it

Q=mc(delta)T
=(4)(449J/kgK)(Tf-973)=(20)(4190J/kgK)(Tf-298)

i think I'm doing this question wrong because .. when i solve for Tf i get a negative number of -288.66K

help?
 
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nvm forget this question i just figured out how to do it... i forgot to put the negative sign for the iron since it loses heat.
 

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