Thermodynamics: 2 Pistons connected by a rod

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SUMMARY

The discussion focuses on a thermodynamics problem involving two pistons connected by a rod, emphasizing the application of the First Law of Thermodynamics, U = Q - W. The scenario is defined as adiabatic due to insulation, leading to the conclusion that internal energy change (U) equals the negative of work done (W). The participants analyze the force equilibrium between the pistons and derive that the work done is zero when considering the system's total energy, despite the complexities introduced by non-constant pressure and friction.

PREREQUISITES
  • Understanding of the First Law of Thermodynamics
  • Knowledge of adiabatic processes and their characteristics
  • Familiarity with force equilibrium in mechanical systems
  • Basic principles of gas behavior in thermodynamic systems
NEXT STEPS
  • Study the implications of adiabatic processes in thermodynamics
  • Learn about calculating work done in non-constant pressure scenarios
  • Explore the concept of force equilibrium in multi-piston systems
  • Investigate the effects of friction on thermodynamic processes
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Students and professionals in mechanical engineering, thermodynamics enthusiasts, and anyone studying the principles of energy transfer in piston systems.

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Homework Statement


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Homework Equations



First Law, U = Q-W
We also need to apply a force equillibrium on the pistons

The Attempt at a Solution


Since the problem says the walls and pistons are insulated, we know there is no heat transfer and the process is adiabatic but not reversible because of friction. So U = -W. I don't know the path and so I don't know how I could determine the work done but if I consider the system which contains both gases, the pistons and the rod (and the case where atm pressure = 0) then the work done is just 0 so U = 0. Therefore naCv(T2-T1)+nbCv(T2-T1) = 0. I also know that for final pressures, the forces acting on the rod must balance so pressure A*piston area of A = pressure B*piston area of B.

Beyond this I'm not so sure what to do since I don't know much on the final state variables. What confuses me most is how it would be possible to calculate work since the pressure is not constant and the path is unknown.
 
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The net work is indeed zero (neglecting the forces of friction). However, the work of gas in one cylinder must be equal to the work on gas in the other cylinder. You could also note that the changes of volumes in both cylinders are related quite simply.
 

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