Thermodynamics and Concentrated Solar Power

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Discussion Overview

The discussion revolves around the efficiency of thermal solar collectors and the conversion of heat into electricity, particularly through the use of peltier devices. Participants explore the theoretical and practical aspects of efficiency in this context, including the impact of temperature differences and heat recirculation.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant expresses interest in building a thermal solar collector and notes the inefficiency of converting heat to electricity, citing a typical efficiency of 10% for peltier devices.
  • Another participant points out that the cold side of the peltier device requires cooling, which affects its efficiency due to the temperature difference needed for optimal operation.
  • A third participant mentions the theoretical maximum efficiency for heat to electricity conversion, referencing Carnot's theorem and providing a calculation based on specific temperature values.
  • There is a suggestion that recirculating heat after the peltier device might improve efficiency, although this is questioned by others regarding the actual losses involved.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the efficiency of the system or the implications of recirculating heat. Multiple competing views regarding the efficiency of peltier devices and the overall system remain present.

Contextual Notes

Participants discuss various assumptions regarding temperature differences, cooling requirements, and the impact of heat losses, which are not fully resolved in the conversation.

Strat-O
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I am interested in building a thermal solar collector. I'm mostly interested in using the heat directly but there's always a need for electricity. The trouble is converting heat into electricity is pretty inefficient no matter how you do it. Consider a peltier device. A typical one, depending on your delta T might convert the heat energy at an efficiency of 10%.

In the attached diagram There is a parabolic dish that is 70% efficient and a peltier device that is 10% efficient, so the efficiency of the system in generating electricity is 7%, right? (neglecting heat losses due to lousy insulation)

Someone suggested that because the heat is recirculated after the peltier device that it was somehow more efficient than 10%.

Any thoughts?
 

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What you haven't drawn is that the cold side of the peltier device has to be cooled.
The efficiency of the peltier device will depend on the temperature difference across it, so you'll need a radiator, or cooling water.
So there's a further loss, because the temperature difference across the peltier device itself will be less than the temperature difference between the tank and the outside air or cooling water.
Your efficiency also will go way down when the tank begins to cool if there's no more sun.
If the device gets 80C water from the tank and sends 60C water back to the tank, the heat from the return water isn't lost, but that wasn't included in the efficiency of the peltier device anyway. The reject heat on the cold side is probably lost, unless you can heat your house with it.
 
Strat-O said:
converting heat into electricity is pretty inefficient no matter how you do it.
As perhaps you know, the theoretical maximum efficiency is determined by the temperatures involved. If the collector can get up to 530C (800K) and you have a cooling fluid available at 30C (300K) then the theoretical efficiency is 1 - 300/800 = 62.5%.
 
Thanks for the responses.

So the 63.5 percent is from the formula for Carnot's theorem. I've seen it before but I think I've got it commited to memory now by seeing it stated so simply.

Marlin
 

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