Thermodynamics chemical reaction problem

[Benzoate]

Homework Statement

What are q and w (in kJ) for the reaction of 22 g of Na(s) and 82 g of Cl2(g) to produce NaCl at 1 atm and 298 K.

Homework Equations

w=-delta(n(g))* R*T where delta(n(g)) = the moles of gas created during the reaction

The Attempt at a Solution

First, I wrote the chemical reaction for Na and Cl2

2Na(s) +Cl2(g)=> 2NaCl

delta(n(g))=0-1 = -1

82 g Cl2*(1 mol Cl2/70.98 g Cl2)*(-1 mol gas/1mol Cl2)= -1.16

delta n(g) =-1.16
w=-delta(n(g))*RT=(-1.16)(8.314)(298 K)=2.87 kJ

But that's not the answer according to the back of my textbook.

 

[Astronuc]

The volume is changing from the volume of Cl₂ gas to essentially zero.

Can one apply w = p $\Delta{V}$? 1 mole of gas has a volume of 22.4 l.

Then there is the heat.

 

[Blueshift5]

Your attempt at a solution is correct, however there may be a mistake in the given values or the answer in the textbook. It is always important to double check your calculations and make sure you are using the correct values and units. If you are still unsure, you can seek help from your instructor or a classmate.