- #1

- 22

- 0

Im trying to do an assingment for second year BSc, ive thrown alot of effort into quatum this semester so have fallen a little behind with thermodynamics so help is appreciated!

Calculate the change in entrupy of the universe for the following processes

A can of beer, at initial temperature of 4 degrees C, and of heat capacity 2500JK^1 , is allowed to reach thermal equilibrium with its surroundings at 30 degrees C

https://www.physicsforums.com/latex_images/24/2495626-1.png [Broken]

Copied the formulas so hoping they have come out alright.

if the can has to increase temperature by 26 degrees K then needs to gain 65000 J of heat energy.

the surroundings must lose 65000J of heat energy so:

65000/277 + 65000/303 = 449.18 J / K

Its not a many mark question but i dont feel confident ive done it right.

Cheers for any help in advance.

Khris

## Homework Statement

Calculate the change in entrupy of the universe for the following processes

A can of beer, at initial temperature of 4 degrees C, and of heat capacity 2500JK^1 , is allowed to reach thermal equilibrium with its surroundings at 30 degrees C

## Homework Equations

https://www.physicsforums.com/latex_images/24/2495626-1.png [Broken]

Copied the formulas so hoping they have come out alright.

## The Attempt at a Solution

if the can has to increase temperature by 26 degrees K then needs to gain 65000 J of heat energy.

the surroundings must lose 65000J of heat energy so:

65000/277 + 65000/303 = 449.18 J / K

Its not a many mark question but i dont feel confident ive done it right.

Cheers for any help in advance.

Khris

Last edited by a moderator: