Thermodynamics, find the work done from the graph

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SUMMARY

The discussion focuses on calculating the work done in a thermodynamic system using a pressure-volume graph. The work is determined by the area under the curve between points A, B, and C, with specific pressure values at each point. The initial calculations provided by users were incorrect due to misunderstanding the pressure values at points A and B. The correct approach involves integrating the area under the red lines between vertical lines at points A and C, leading to a final work calculation of 180 J.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically work and energy.
  • Familiarity with pressure-volume (PV) graphs.
  • Knowledge of how to calculate area under a curve in a graph.
  • Basic algebra for manipulating equations and calculating work done.
NEXT STEPS
  • Review the concept of pressure-volume work in thermodynamics.
  • Learn how to calculate work done using integration techniques.
  • Study the relationship between pressure, volume, and work in various thermodynamic processes.
  • Explore examples of pressure-volume graphs and their corresponding work calculations.
USEFUL FOR

Students studying thermodynamics, engineers working with energy systems, and anyone interested in understanding the principles of work done in thermodynamic processes.

Alice7979
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Homework Statement


Using the data presented in the accompanying pressure-versus-volume graph, estimate the work done (including the algerbraic sign) when the system changes from A to B to C along the path shown.

Homework Equations


The work done is the area from change in position and time
Work= PV

The Attempt at a Solution


I counted 5X6 from the initial position to the next for both AB and BC
Given 1000 Pa and .002 m^3
Work = 1000 * .002 *60 = 1200 J

Do I have to include the whole area under the red lines starting from A to C?
 

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Alice7979 said:

Homework Statement


Using the data presented in the accompanying pressure-versus-volume graph, estimate the work done (including the algerbraic sign) when the system changes from A to B to C along the path shown.

Homework Equations


The work done is the area from change in position and time
Work= PV

The Attempt at a Solution


I counted 5X6 from the initial position to the next for both AB and BC
Given 1000 Pa and .002 m^3
Work = 1000 * .002 *60 = 1200 J

Do I have to include the whole area under the red lines starting from A to C?
Write down your answer completely, consider the value of P at A and B, correctly. Neither at A nor at B it is 1000 Pa. Think carefully they need to be different.
 
Alice7979 said:

Homework Statement


...Do I have to include the whole area under the red lines starting from A to C?...

Draw a vertical (vertical to the volume axis) line at A and another vertical line at C. At point A the vertical line is just an extension to the red line at A.

You have to include all the area under the red lines which is between those two vertical lines.
 
I think it will be useful to answer the following questions:

What's the pressure at point B?
What's the pressure at point C?

And how you will calculate the total work if you know correctly these two pressures?
 
Delta² said:
I think it will be useful to answer the following questions:

What's the pressure at point B?
What's the pressure at point C?

And how you will calculate the total work if you know correctly these two pressures?
I am still lost but the graph shows 1000 Pa 10 blocks up starting from 0 so would the pressure per block be 100 Pa? Then change in pressure (final to initial) is 10000. And the volume per block is .002 so I multiplied it by 12 blocks and got .024. The work done would be P*V so 10000* 240. I If I'm wrong, am I even close to getting it?
 
Alice7979 said:
It sounds like it should be
Should be what?
Alice7979 said:
is the correct answer 180 J
Not even close.
Alice7979 said:
the graph shows 1000 Pa 10 blocks up starting from 0
Are we looking at the same graph?
It shows that each little square is 104Pa vertically and 2x10-3m3 horizontally. So what work does one little square represent?
 
I just noticed that, I got it now. Thanks
 

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