Thermodynamics: Finding Specific Heat of Ice

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Homework Statement


It takes 15 seconds to warm ice 15 degrees ( -15 degrees celsius to 0 degrees celsius). The ice has a mass of .25 kg. The energy is supplied at 530 W to the ice.

Homework Equations


Q = mc delta T


The Attempt at a Solution


I plugged in all the information for Q
(15 seconds * 530 W) = .25 * c * 15 degrees
which ends up with c = 2120

Did I do this correctly
 
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