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Thermodynamics: Finding Specific Heat of Ice

  1. Apr 26, 2009 #1
    1. The problem statement, all variables and given/known data
    It takes 15 seconds to warm ice 15 degrees ( -15 degrees celsius to 0 degrees celsius). The ice has a mass of .25 kg. The energy is supplied at 530 W to the ice.

    2. Relevant equations
    Q = mc delta T


    3. The attempt at a solution
    I plugged in all the information for Q
    (15 seconds * 530 W) = .25 * c * 15 degrees
    which ends up with c = 2120

    Did I do this correctly
     
  2. jcsd
  3. Apr 26, 2009 #2

    mgb_phys

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    You might want to add some units - but correct method
     
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