Thermodynamics, Helmholtz free energy, Legendre transformation

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SUMMARY

The Helmholtz free energy for the system is defined as F(T,V) = -\frac{VT^2}{3}. To calculate the internal energy U(S,V) using a Legendre transformation, the relationship U = F + TS is utilized. The entropy S is derived as S = -\left(\frac{\partial F}{\partial T}\right)_V = -\frac{2}{3}VT. The final expression for U is found to be U = -VT^2, which depends on V and T rather than S and V. The discussion emphasizes the need to express T in terms of S for a complete transformation.

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  • Knowledge of Legendre transformations in thermodynamics
  • Familiarity with partial derivatives and their physical significance
  • Basic principles of thermodynamic potentials and their interrelations
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SoggyBottoms
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Homework Statement



The Helmholtz free energy of a certain system is given by F(T,V) = -\frac{VT^2}{3}. Calculate the energy U(S,V) with a Legendre transformation.


Homework Equations



F = U - TS
S = -\left(\frac{\partial F}{\partial T}\right)_V


The Attempt at a Solution



We have U = -\frac{VT^2}{3} + TS. S is given by S = -\left(\frac{\partial F}{\partial T}\right)_V = -\frac{2}{3}VT. Then:

U = -\frac{VT^2}{3} - \frac{2}{3}VT^2 = -VT^2

Now I didn't end up with a function U that depends on S and V, but on V and T instead. Should I somehow describe T in terms of S instead? If so, how can I do that?
 
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SoggyBottoms said:

Homework Equations



F = U - TS
S = -\left(\frac{\partial F}{\partial T}\right)_V

The Attempt at a Solution



We have U = -\frac{VT^2}{3} + TS. S is given by S = -\left(\frac{\partial F}{\partial T}\right)_V = -\frac{2}{3}VT. Then:
Check the sign of S: it is 2/3 VT .
Having this relation between T, V and S, express T as function of S and V and substitute into the expression for U.

ehild
 

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