Thermodynamics Problem with a Vacuum

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SUMMARY

The discussion focuses on a thermodynamics problem involving one mole of a monatomic ideal gas expanding into a vacuum. Key calculations include work (w), internal energy change (ΔU), enthalpy change (ΔH), and entropy change (ΔS). The gas expands freely, resulting in no heat exchange (q = 0) and no work done (w = 0), leading to ΔU = 0 and ΔH = 0. The entropy change (ΔS) can be calculated using the formula ΔS = qrev/T, which simplifies in this scenario due to the lack of heat transfer.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Familiarity with ideal gas laws
  • Knowledge of thermodynamic processes (adiabatic, isothermal, etc.)
  • Basic concepts of entropy and heat transfer
NEXT STEPS
  • Study the first law of thermodynamics in detail
  • Learn about ideal gas behavior and equations of state
  • Explore different thermodynamic processes and their characteristics
  • Investigate entropy calculations in non-heat transfer scenarios
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Students studying thermodynamics, educators teaching gas laws, and anyone interested in understanding the principles of gas expansion in vacuum conditions.

kalbuskj31
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Homework Statement



Calculate q, w, ΔH, ΔU, ΔS for the following problem: One mole of a monatomic ideal gas starting at 300K, and 10 atm, the gas freely expands into a vacuum to triple its volume.


Homework Equations



w = PΔV,
ΔU = q - w or Cv dT,
ΔH = ΔU + PΔV or Cp dT,
ΔS = qrev/T,
q = ?


The Attempt at a Solution



I'm having trouble understanding how the concept of the vacuum affects things such as temperature and pressure. Do temperature and/or pressure remain constant? I'm confused how to start this problem, since I can't identify the type of situation (adiabatic, isothermal, isobaric, etc.) this creates. Explanation on the effect a vacuum has would be very helpful.

Kyle
 
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They're just saying vacuum to make it clear that there isn't anything else there. After the expansion, the initial gas has simply filled a larger volume.
 
I'm not going to answer your question directly, but I'll give you some hints. Since it is in a vacuum, will there be any heat put into or taken away from the system? Is any work applied to or from the gas (actually this question can be complicated depending on how you look at it)?
 

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