Thermodynamics Questions dealing with Entropy

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SUMMARY

The discussion focuses on thermodynamics, specifically addressing entropy and the First Law of Thermodynamics in the context of a hot brick placed in cold water within an adiabatic enclosure. The participants clarify that "adiabatic" means no heat transfer occurs between the system (brick and water) and the surroundings, not between the brick and water themselves. The temperature of the brick will decrease while the water's temperature will increase, but the total heat exchange is zero due to the adiabatic condition. Understanding these principles is crucial for accurately applying thermodynamic laws.

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  • Understanding of thermodynamic systems and surroundings
  • Knowledge of the First Law of Thermodynamics (dU=dQ-dW)
  • Familiarity with the concept of adiabatic processes
  • Basic principles of entropy in thermodynamics
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  • Study the implications of adiabatic processes in thermodynamics
  • Explore detailed examples of entropy calculations in closed systems
  • Learn about the relationship between temperature changes and energy transfer
  • Investigate real-world applications of the First Law of Thermodynamics
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Students of thermodynamics, physics educators, and anyone seeking to deepen their understanding of energy transfer and entropy in closed systems.

ana111790
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My teacher gave us a packet of questions, I am stuck on a few:
Part 1)

Homework Statement


A hot brick is tossed into cold water, and this is an adiabatic enclosure. The volume of the brick and water will not change.

Define the system and surroundings.

Homework Equations

Entropy Tot = Entropy of system + Entropy of surroundings

The Attempt at a Solution


I am assuming the water is the surroundings, and the brick the system, or is it supposed to be a tricky question?

Part 2)

Homework Statement

What will happen in terms of temperature changes, after the brick is tossed into the water? Is this answer based on the First Law of Thermodynamics? Explain why or why not.

Homework Equations

First Law of Thermodynamics: dU=dQ-dW

The Attempt at a Solution

I am pretty sure that the brick's temperature will go down, and the water's temperature will go up, but it sais that the process is adiabatic so no Heat is given of. I am not sure how to relate these two, maybe there will be no Temp. change?

Part 3)

Homework Statement

What will be Utotal for the process described in part 2? Explain your reasoning.Is the answer based on an application of the 1st Law of thermodynamics? Explain why or why not.

Homework Equations

First Law of Thermodynamics: dU=dQ-dW

The Attempt at a Solution

U=W, because the process is adiabatic, not Q is given of. How do I relate it to 1st Law of Thermo then?
Thank you so much for any help!
 
Last edited:
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Hi ana. Welcome to the board. :smile:

When they say "adiabatic" they don't mean there is no heat transfer between the water and brick, they mean there is no heat transfer between the water + brick and the surroundings. In other words, consider the water and brick being inside a perfectly insulated bath tub.

Does that help at all?
 
It does help indeed!
Thank you for the clarification! :smile:
 

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