Thermodynamics: Vapor Compression Refrigeration that is Adiabatic?

Click For Summary

Discussion Overview

The discussion revolves around the vapor-compression refrigeration cycle, specifically focusing on calculating the coefficient of performance (COP) for a heat pump system using refrigerant-134a. Participants explore the implications of adiabatic conditions and the insulation of devices in the cycle.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents a scenario involving a heat pump operating with refrigerant-134a, noting the need to find the COP but expressing difficulty in determining QH due to the insulation of the devices.
  • Another participant provides a formula for COP and suggests using specific enthalpy values at various points in the cycle to calculate the COP, indicating the importance of mass flow rate and enthalpy differences.
  • A correction is made regarding the state conditions at various points in the cycle, with a participant updating the temperatures and pressures for accuracy in the calculations.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the calculation method for COP, as there are differing approaches and corrections presented without a clear resolution on the best path forward.

Contextual Notes

Limitations include the assumption of well-insulated devices, which affects the ability to determine heat transfer values directly. There are also unresolved steps regarding the calculation of enthalpy at specified points.

Sara1
Messages
10
Reaction score
0
Consider a heat pump works on the vapor-compression refrigeration cycle with 0.2 kg/s of refrigerant-134a as the working fluid. The cycle is used to maintain a house at 26oC while absorbing heat from the outdoors at 3oC. R-134a enters the compressor at 200 kPa as a saturated vapor and leaves at 900 kPa, 50oC. The refrigerant leaves the condenser as a saturated liquid. Assuming the four devices to be well-insulated:

I need to find COP, but in order for that i need QH, which i can't have because all the devices are insulated. How do i proceed?
 
Physics news on Phys.org
COP (heating)=Q-hot/W-net,in

COP (heating)=M-dot * (h2-h4)/m-dot * (h2-h1)

Pt 1: 200 kPa,3 C
Pt 2: 900 KPa,50 C
Pt 4: 900 KPa, 26 C

See if that works
 
Correction

Pt 1:200 kPa, sat. Vapor, -9 C

Pt 2: 900 kPa, 50 C

Pt 4: 900 kPa, sat. liquid, 35.4 C

Find enthalpy' s for various points, use equation for COP-heat
 
Thank you
 

Similar threads

Replies
1
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
6K
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 8 ·
Replies
8
Views
6K