- #1

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W= (P1V1-P2V2)

= mR(T1-T2)/n-1

AS we know R/n-1 = Cv and Cp/Cv=1 also considering m=1

W=Cv(T1-T2)

but in textbook it is quoted as

W=Cp(T1-T2)

please can u help me in solving this.( i found this during deriving Brayton cycle)

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- Thread starter kaundinya
- Start date

- #1

- 2

- 0

W= (P1V1-P2V2)

= mR(T1-T2)/n-1

AS we know R/n-1 = Cv and Cp/Cv=1 also considering m=1

W=Cv(T1-T2)

but in textbook it is quoted as

W=Cp(T1-T2)

please can u help me in solving this.( i found this during deriving Brayton cycle)

- #2

Chestermiller

Mentor

- 21,277

- 4,725

The adiabatic compression step and the adiabatic expansion step in the Brayton cycle takes place in an open system operating at steady state, with gas flowing through the system. For such circumstances, you need to use the flow form of the first law, which focuses on each parcel of mass flowing through the system. The form of the first law that applies here is Δh=-w

W= (P1V1-P2V2)

= mR(T1-T2)/n-1

AS we know R/n-1 = Cv and Cp/Cv=1 also considering m=1

W=Cv(T1-T2)

but in textbook it is quoted as

W=Cp(T1-T2)

please can u help me in solving this.( i found this during deriving Brayton cycle)

Chet

- #3

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thank you

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