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Thevenin AC Circuit Homework: Solve & Analyze Results
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[QUOTE="dwn, post: 4756818, member: 465592"] [h2]Homework Statement [/h2] Image Attached [h2]Homework Equations[/h2] Thevenin, Series, Parallel [h2]The Attempt at a Solution[/h2] j10(12-j34) / (j10+12-j34) = (340 + 120j) / (12/j24) 1.67 + j13.3 or 13.44∠82.4° Now why can't I just use this equivalent resistance and multiply by the current source (22∠30°) to find the Thevenin Voltage? The result of doing this is 295.68∠112.8°V. Instead, the book uses Nodal Analysis to find V[SUB]TH[/SUB], which results in 295.3∠115.889°V. Why do the voltages roughly match, but the phase angles do not? Do you think book made mistake? [/QUOTE]
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Thevenin AC Circuit Homework: Solve & Analyze Results
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