Thevenin AC Circuit Homework: Solve & Analyze Results

Click For Summary
SUMMARY

The discussion focuses on solving a Thevenin AC circuit problem involving complex impedance and Nodal Analysis. The user calculated the Thevenin voltage using an equivalent resistance method, yielding a result of 295.68∠112.8°V, while the textbook solution using Nodal Analysis provided 295.3∠115.889°V. The discrepancy in phase angles raises questions about potential errors in the textbook. The user is encouraged to verify the steps in the textbook for possible mistakes.

PREREQUISITES
  • Understanding of Thevenin's theorem in AC circuits
  • Familiarity with complex impedance calculations
  • Knowledge of Nodal Analysis techniques
  • Proficiency in converting between rectangular and polar forms of complex numbers
NEXT STEPS
  • Review Thevenin's theorem applications in AC circuit analysis
  • Study Nodal Analysis in detail, focusing on AC circuits
  • Practice converting complex numbers between rectangular and polar forms
  • Investigate common errors in textbook solutions for circuit analysis problems
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in AC circuit analysis and Thevenin equivalent circuits.

dwn
Messages
165
Reaction score
2

Homework Statement



Image Attached

Homework Equations



Thevenin, Series, Parallel

The Attempt at a Solution



j10(12-j34) / (j10+12-j34) = (340 + 120j) / (12/j24)

1.67 + j13.3 or 13.44∠82.4°

Now why can't I just use this equivalent resistance and multiply by the current source (22∠30°) to find the Thevenin Voltage? The result of doing this is 295.68∠112.8°V. Instead, the book uses Nodal Analysis to find VTH, which results in 295.3∠115.889°V.
Why do the voltages roughly match, but the phase angles do not? Do you think book made mistake?
 

Attachments

  • Screen Shot 2014-05-25 at 7.00.24 PM.jpg
    Screen Shot 2014-05-25 at 7.00.24 PM.jpg
    3.3 KB · Views: 526
Physics news on Phys.org
dwn said:

Homework Statement



Image Attached

Homework Equations



Thevenin, Series, Parallel

The Attempt at a Solution



j10(12-j34) / (j10+12-j34) = (340 + 120j) / (12/j24)

1.67 + j13.3 or 13.44∠82.4°

Now why can't I just use this equivalent resistance and multiply by the current source (22∠30°) to find the Thevenin Voltage? The result of doing this is 295.68∠112.8°V. Instead, the book uses Nodal Analysis to find VTH, which results in 295.3∠115.889°V.
Why do the voltages roughly match, but the phase angles do not? Do you think book made mistake?

Your analysis looks okay. It's quite possible for a text to have a typo or mistake. If the book presents all the steps of their solution, perhaps you can spot where their error has occurred.
 

Similar threads

Engineering How to Calculate Thevenin Equivalent Circuit
  • · Replies 5 ·
Replies
5
Views
3K
Engineering Thevenin Equivalent of AC RLC Circuit w/ Dependent Voltage
  • · Replies 2 ·
Replies
2
Views
4K
Engineering Solving circuit with Thevenin's theorem
  • · Replies 4 ·
Replies
4
Views
2K
Engineering Finding Thevenin Equivalent Circuit for a Complex Network
  • · Replies 7 ·
Replies
7
Views
3K
Thevenin's Theorem, Superposition & Norton's Theorem
  • · Replies 28 ·
Replies
28
Views
7K
AC nodal anaylsis to find V thevenin
  • · Replies 5 ·
Replies
5
Views
2K
Engineering Thevenin Theorem seems to not work in this 1 bit RAM RC circuit
  • · Replies 2 ·
Replies
2
Views
2K
Engineering How Do You Determine Thevenin Equivalent Circuits and Maximize Power Transfer?
  • · Replies 3 ·
Replies
3
Views
2K
Engineering Finding Thevenin's equivalent circuit for AC network
  • · Replies 1 ·
Replies
1
Views
4K
Engineering Find load impedance / (Thevenin / Norton too) with RLC & AC circuit?
  • · Replies 13 ·
Replies
13
Views
4K