Thevenin equivalent with opposite direction loops

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Bill13
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Hi all! I need some help with a thevenin problem(attachment).I have searched all the web but all the solutions are for same direction loops.

Here is my attempt until now:

Rth=100*50/150=33.3Ω

Ι= 10+10/150=0.13Α

Vab=10-(50*13)=10-6.5=3.5v

Thanks! :biggrin:
 

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You have Rth correct, and despite writing an incorrect statement for the current, you handled it as though you had written it properly (you need parens) and got that right too.

Your Vth is not correct.