- Homework Statement:
- Find the thevenin and norton equivalents of the circuit.
- Relevant Equations:
- KCL, Nodal Analysis, Thevenin and Norton Equivalents
so when I did this problem I did nodal analysis to find the voltage across the 40k resistor, and found it to be 16V. From there I did two source transformations, combined the sources and did some equivalent resistance to get the answer as seen below:
However this differed from the answer he gave which was 3mA with a 5.33k resistor as seen below:
So when I went to check and look at it I think the answer may be wrong, both that is. You have a current source that is dependent on IA, however IA is dependent on what the circuit is hooked up to, as you essentially have a current divider. So the current is going to be dependent on the circuit attached, as is the dependent source, so it seems to be like the answer should be a function as opposed to a hard answer.The essence of Thevenin and Norton equivalents is that they are a way to simplify the circuit but be functionally equivalent. So to verify this I did out a "test" of sorts by hooking up the circuit, both in its original form and its Thevenin and Norton equivalents, at an arbitrary resistor (I chose 1k). These three should be functionally equivalent with respect to the 1k resistor, however as seen below that is not what I found:
I did out nodal analysis for the equivalent circuit and got a different voltage across the 1k resistor than when I used the Norton/Thevenin equivalents. I think, as I mentioned before, this is due to the dependency of the voltage source on the current which can be affected by what is hooked up to the circuit, meaning that the answer should be a function rather than a simple number, as dependent upon the resistance of the circuit hooked up it could affect the internal equivalency of the circuit.
I just wanted to post on here, where all these really big brain physics people reside, before I approach my professor about it and make sure my thinking is right. Cause I may very-well be wrong here, certainly wouldn't be the first time. Thanks for reading and sorry for the bad photos.