Thin Film Interference in Glass Plates: How Many Bright Fringes Will Be Seen?

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A broad beam of light with a wavelength of 683nm is directed through a pair of glass plates that are 120mm long and separated by a wire of 0.048mm diameter. The air gap between the plates acts as a thin film, creating conditions for thin film interference. To determine the number of bright fringes visible to an observer, the optical path difference must be calculated, considering constructive interference conditions. The equation 2n_air * d = mλ is relevant for solving this, where m represents the order of interference. The finite size of the plates limits the number of observable bright fringes.
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Homework Statement



A broad beam of light, of wavelength 683nm is sent directly down through the top plate of a pair of glass plates. The plates are 120mm long, touch at the left end and are separated by a wire of a diameter .048mm at the right end. Air between the plates act as a thin film. How many bright fringes will be seen by an observer looking down through the top plate?

Homework Equations



Perhaps Snell's Law
Perhaps a calculation for the optical path difference.

The Attempt at a Solution



I am really just not sure where to start with this. I have been plagued by these types of optics questions for a while. I think I basically have to calculate the Optical path difference and that will account for either constructive or destructive interference of the light, with an appropriate wavelength multiple added on to it.

I am not sure why there would be a limit on the number bright fringes seen by the observer looking down at the plates. I guess that is due to the finite size of the plate.

Is it just,
$$2n_{\text{air}}d=m\lambda$$
and solve for m? If so, why?
 
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I think I need to do an integration summing up the m's for all the values of d. Because the plates go from 0mm separation to .048 mm separation.
 
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