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## Homework Statement

Upon using Thomas Young's double slit experiment to obtain measurements, the following data was obtained. Use this data to determine the wavelength of light being used to create the interference pattern.

**DO this in 3 different ways!**

- The Angle to the Eighth maximum is 1.12 deg.
- The distance from the slits to the screen is 3.02 m
- The distance from the first minimum to the fifth minimum is 2.95 cm
- The distance between the slits is 0.00025 m

## Homework Equations

sin∅

_{n}=(n-1/2)λ/d

sin∅

_{m}=mλ/d

Δx=Lλ/d

X

_{n}/L=(n-1/2)λ/d

X

_{m}/L=mλ/d

## The Attempt at a Solution

sin∅

_{n}=(n-1/2)λ/d

λ=(sin1.12)(0.00025)/(7.5)

**λ=651 nm**

The distance from the first minimum to the fifth minimum is 2.95 cm .. therefore

4Δx=2.95 cm

Δx=0.0074 m ( i converted it)

__Im unsure about 4 x if anyone can shed any light on that that would be cool__Δx=Lλ/d

λ=Δxd/L

λ=(0.0074) (0.00025)/ (3.02)

λ= 612 nm

__as for this one I dont know if I should use the X___{m}or X_{n}equation..I usedX

_{m}/L=mλ/d

(0.0295)/3.02=4λ/(0.00025)

λ= 610 nm

__Number seems plausible but it also does when I use the X___{n}equationthanks for any help in advance