1. The problem statement, all variables and given/known data A baseball player throws a ball at an initial velocity of 27m/s. It lands 140m away at 6.4 seconds. (A) what is the angle he threw it at? (B) what is the maximum height? 2. Relevant equations 3. The attempt at a solution I found the angle to be 36 degrees using the formula d=ViΔt+1/2aΔt^2 140 = 27cosθ(6.4) 140/6.4 = 27cosθ θ=36 degrees However when I went to calculate the maximum height I I subbed it into my formula: dxmax= 27sin36•3.2+1/2(-9.81)•3.2^2 dxmax=0.5574m Which I find quite unreasonable?