Three girls pull a sled. Determine the acceleration.

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Homework Help Overview

The problem involves two girls pulling a sled across snow while a third girl exerts a backward force. The goal is to determine the instantaneous acceleration of the sled, which has a specified mass.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss finding the net force acting on the sled and consider the vector nature of forces. There are attempts to break down the forces into horizontal and vertical components, and questions are raised about the meaning of "instantaneous" in the context of the problem.

Discussion Status

Some participants have provided guidance on how to approach the problem by considering the vector addition of forces. There is an ongoing exploration of the calculations involved, with one participant expressing uncertainty about their results and the implications of the term "instantaneous."

Contextual Notes

Participants note a numerical error in one of the calculations and discuss the implications of forces not being constant over time.

Natko
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Homework Statement


Two girls pull a sled across a field of snow, as shown in the diagram. A third girl pulls backward with a 2.0 N force. If the mass of the sled is 10 kg, determine its instantaneous acceleration.
Screenshot (104).png


Homework Equations


F=ma

The Attempt at a Solution


Sorry, I'm stumped.
 
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You want to find the net force on the block. Do you have any ideas about how to work this out?
 
To give some further input:

1) forces (pulling) are vectorial, which means they can be added by "putting them tip on tail". So, the net force is the sum over all forces.
2) Can you somehow determine the horizontal and vertical component of the forces?
 
BOYLANATOR said:
You want to find the net force on the block. Do you have any ideas about how to work this out?

MortalWombat said:
To give some further input:

1) forces (pulling) are vectorial, which means they can be added by "putting them tip on tail". So, the net force is the sum over all forces.
2) Can you somehow determine the horizontal and vertical component of the forces?

Thanks for the tips. I'll try:

Fy=10sin30-10sin40
=-1.428 N
Fx= 10cos30+10cos40-2
=14.32 N
√(Fy2+Fx2)=14.39 N
Θ=tan-1(Fy/Fx)
=5.67
a=F/m
=1.439 m/s2 [5.67 down of left]

Is that correct, or did I mess up somewhere? What does the question mean by "instantaneous?" I know what the word means, but how does it affect this question?
 
Last edited:
Natko said:
Thanks for the tips. I'll try:

Fy=10sin30-10sin40
=-4.28 N

Numerical error in here. The rest of the working looks good
 
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Instantaneous means happening at this instant. It is unlikely that the girls could all pull with constant force in a constant direction for an extended time.
 

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