Three Phase Troubleshooting: Calculating Voltage & Current

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SUMMARY

The discussion focuses on calculating phase voltage and current in a balanced three-phase power system with a delta-connected load of 30 + 18.86j ohms and a line voltage of 400V. The user, Rob, correctly identifies that the line and phase voltage are equal at 400V, but encounters an issue with the phase angle during calculations. The impedance is calculated as 35.43 ohms at an angle of 32.14 degrees, leading to a current calculation of 11.29 A at -32.14 degrees. The discrepancy in phase angle suggests a misunderstanding of the relationship between line and phase voltages.

PREREQUISITES
  • Understanding of three-phase power systems
  • Knowledge of complex impedance and phasor representation
  • Familiarity with delta and wye (star) connections
  • Ability to perform calculations involving voltage, current, and impedance
NEXT STEPS
  • Study the relationship between line and phase voltages in three-phase systems
  • Learn about the differences between line current and phase current
  • Explore the concept of phasor diagrams for three-phase circuits
  • Investigate the implications of phase angles in AC circuit analysis
USEFUL FOR

Electrical engineers, students studying power systems, and professionals involved in three-phase circuit analysis will benefit from this discussion.

robcowlam
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Hi guys,
Im having some trouble with a question about 3 phase power system. I have a balanced delta connected load of 30+18.86j ohms. The voltage is given as 400v @Hz and I am asked to calculate the phase voltage and current using the voltage Vr as the reference.

Now from my knowledge of 3 phase I understand that with this type of load the line and phase voltage are the same (400v) with each phase 120deg lagging from the previous.

Z= 30+18.86j = 35.43 @ 32.14degrees
This leads me to do the calculation:
I = V/Z = (400 @ 0 degrees)/35.43 @ 32.14degrees = 11.29 @ -32.14 degrees.
Repeating this for the other 2 phases gives answers with +/- 120degrees

The magnitude is correct however the angle is 30 degrees out and I cannot see why, the only thing I can think of is that the line voltage is 30degrees out of phase with the phase voltage which I am using as the reference.

Does anyone have any idea if this might be a correct assumption?

Thanks in advance,
Rob
 
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There is a difference in line current and phase current. What is your target variable?
 

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