Threshold Frequency of Metal: 1.83e48Hz

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SUMMARY

The threshold frequency of the metal tin is calculated to be 1.83e48 Hz based on the photoelectric effect. Using Planck's equation, where the frequency of incident light (1.21e15 Hz) is related to the maximum kinetic energy of emitted photoelectrons (1.96 eV), the calculation confirms the threshold frequency. The formula applied is Planck's Constant multiplied by frequency equals the sum of Planck's Constant multiplied by the threshold frequency and the maximum kinetic energy. The correct application of this formula yields the established threshold frequency for tin.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Familiarity with Planck's Constant (6.63e-34 J·s)
  • Knowledge of kinetic energy in electron volts (eV)
  • Basic algebra for solving equations
NEXT STEPS
  • Explore the photoelectric effect and its applications in modern physics
  • Study the implications of threshold frequency in different metals
  • Learn about Planck's Constant and its significance in quantum mechanics
  • Investigate the relationship between frequency, wavelength, and energy in electromagnetic radiation
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Physics students, educators, and researchers interested in quantum mechanics and the photoelectric effect will benefit from this discussion.

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Light of frequency 1.21e15 Hz illuminates a piece of tin, and the tin emits photoelectrons of maximum kinetic energy 1.96 eV. What is the threshold frequency of the metal?
Planck's Constant*Frequency = (Planck's Constant)(Threshold Frequency) + Maximum Kinetic Energy
1.21e15 = (6.63e-34)(x) + (1.96eV)
(1.21e15-3.136e-19)/6.63e-34 = X
Answer I got = 1.83e48Hz

might be in the wrong section, I apologize if it is
 
Physics news on Phys.org
On the LHS, you did not multiply frequency with Planck's Constant.

It is alright other than that.
 

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