Throwing a baseball up in the air

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Homework Help Overview

The discussion revolves around the physics of throwing a baseball straight up into the air, specifically focusing on the magnitudes of acceleration during the throw versus after the ball leaves the thrower's hand.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the acceleration of the baseball while being thrown and after it leaves the hand, questioning the assumptions about the nature of the throw and whether the acceleration is constant.

Discussion Status

Participants are actively engaging with the problem, raising questions about the assumptions made regarding the throw's mechanics and the nature of the forces acting on the baseball. There is recognition that the answer may depend on the specifics of how the throw is executed.

Contextual Notes

There is an emphasis on the need to clarify assumptions regarding the throw, such as whether the arm accelerates uniformly or not, which affects the interpretation of acceleration magnitudes.

cdotter
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Homework Statement


You throw a baseball straight up in the air so that it rises to a maximum height much greater than your height. Is the magnitude of the acceleration greater while it is being thrown or after it leaves your hand? Explain.


2. The attempt at a solution
I'm guessing that the magnitude of the acceleration is greater while it is being thrown. Acceleration is dv/dt. When I throw a ball straight up, velocity goes from 0 to Vmax in less than a second. When the ball leaves my hand, it takes more than a second for the velocity to reach zero then fall back to the ground. Is this correct?
 
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cdotter said:

Homework Statement


You throw a baseball straight up in the air so that it rises to a maximum height much greater than your height. Is the magnitude of the acceleration greater while it is being thrown or after it leaves your hand? Explain.2. The attempt at a solution
I'm guessing that the magnitude of the acceleration is greater while it is being thrown. Acceleration is dv/dt. When I throw a ball straight up, velocity goes from 0 to Vmax in less than a second. When the ball leaves my hand, it takes more than a second for the velocity to reach zero then fall back to the ground. Is this correct?
Your analysis is quite correct, provided the acceleration is uniform while in contact with your hand. But consider this: If the ball is being raised by your arm at constant upward velocity just prior to being thrown, what is the acceleration of the ball just before launch? After being launched what force acts on the ball? What is the ball's acceleration after launch?

AM
 
Last edited:
Andrew Mason said:
Your analysis is quite correct, provided the acceleration is uniform while in contact with your hand. But consider this: If the ball is being raised by your arm at constant upward velocity just prior to being thrown, what is the acceleration of the ball just before launch? After being launched what force acts on the ball? What is the ball's acceleration after launch?

AM
So the magnitude of acceleration after the ball releases from my hand (from gravity) is greater than the magnitude of acceleration with the ball in my hand (from being thrown)?
 
Last edited:
cdotter said:
So the magnitude of acceleration after the ball releases from my hand (from gravity) is greater than the magnitude of acceleration with the ball in my hand (from being thrown)?
It depends on your assumption of how it is thrown.

If one assumes that the throw is made with a constantly accelerating arm, your first answer is correct. But you should state that as your assumption.

I was simply pointing out that if the acceleration is not constant it may not be the case that the magnitude of the acceleration before release is greater than that after. (for example, if the arm accelerates in the first part of the windup but then moves at a fairly uniform speed afterward but before the ball is released).

AM
 
Andrew Mason said:
It depends on your assumption of how it is thrown.

If one assumes that the throw is made with a constantly accelerating arm, your first answer is correct. But you should state that as your assumption.

I was simply pointing out that if the acceleration is not constant it may not be the case that the magnitude of the acceleration before release is greater than that after. (for example, if the arm accelerates in the first part of the windup but then moves at a fairly uniform speed afterward but before the ball is released).

AM

Oh, I understand now. :smile:
 

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