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Throwing a Short Put - simple Distance problem?

  1. May 9, 2010 #1
    1. The problem statement, all variables and given/known data
    Boy throws a shotput at angle of 45Degree which travels a horizontal distance of 30m
    If he releases same shotput at same speed but changes angle to 55 Degree, what will be the new range or distance?
    A) 25m B)41m C)28m D)37m E)32. m

    2. Relevant equations
    That's what i am finding.?/?


    3. The attempt at a solution

    I tried using the info posted somewhere like
    Distance = 1/2 * (acceleration) * (time squared) + (Velocity) * (Initial time) + (Initial Distance)
    But i am not able to get what to put where? what to put in velocity? horizontal or vertical?
    I am not even sure this is correct way.
    Pleas hlp...........driving me nuts!
    Just explain me the concept with equation, if you do not want to solve for me. please
     
  2. jcsd
  3. May 9, 2010 #2

    jack action

    User Avatar
    Science Advisor
    Gold Member

  4. May 9, 2010 #3
    Thanks for your help. That worked nicely :biggrin:
     
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