Time Derivatives: Taking the Time Derivative of (theta dot)^2

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SUMMARY

The discussion focuses on calculating the time derivative of the expression (theta dot)^2, where theta dot represents the first derivative of theta with respect to time. The correct application of the chain rule is essential, leading to the conclusion that the time derivative is 2(theta dot)(theta double dot). This is derived from the general rule for differentiating the square of a function, which states that the derivative of (f(t))^2 is 2f(t)f'(t).

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  • Knowledge of notation for derivatives, such as theta dot and theta double dot
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Fellowroot
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Homework Statement



My question is how do I take the time derivative of (theta dot)^2?


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The Attempt at a Solution



Is the answer just 2(theta double dot)^1 or do you use chain rule 2(theta dot)*(theta double dot)?
 
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Well, assuming theta is a function of time, you must use the chain rule!
 
I take that your "dot" refers to differentiation with respect to time, t,- I will use a prime since it is simpler here- and you are asking about the derivative of (\theta')^2.

The derivative of any (f(t))^2 with respect to t is 2f(t)f'(t), by the chain rule, so the derivative of (\theta(t)')^2 is 2(\theta')(\theta'').
 

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