Time for liquid ejecting from a hole in tank to reach ground

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Discussion Overview

The discussion centers on the time required for liquid ejecting from a hole in a tank to reach ground level, considering the effects of initial velocity due to the liquid's head. Participants explore the validity of a textbook equation for free fall in this context and compare it to projectile motion scenarios.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions whether the equation t = √(2h/g) is valid for liquid ejecting from a hole, given that the liquid has an initial velocity from the head of remaining liquid in the tank.
  • Another participant asks if a horizontal initial velocity matters in this scenario.
  • A participant discusses the objective of determining horizontal distance 'S' and mentions that the textbook uses the time 't' found from the equation in the calculation of 'S' without accounting for initial velocity.
  • Participants analyze a comparison between two bullets: one fired horizontally and one dropped, questioning if they would reach the ground at the same time.
  • One participant references a website to support the idea that vertical and horizontal motions can be treated independently, leading to the conclusion that both bullets would hit the ground simultaneously.
  • A later reply confirms that the time to reach the ground depends only on the initial vertical speed and distance from the ground, stating that horizontal speed does not affect this time.

Areas of Agreement / Disagreement

Participants express differing views on the relevance of initial velocity in the context of the liquid ejecting from the tank. While some agree that horizontal motion does not affect the time to reach the ground, the initial conditions for the liquid's ejection remain a point of contention.

Contextual Notes

The discussion highlights assumptions regarding the independence of vertical and horizontal motions and the implications of initial velocities on the time of descent, which are not fully resolved.

ProgScience
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Hi all,

I was trying to find the time required for liquid ejecting from a hole in a tank to reach ground level. The equation given in one of the books is as follows:

t = √(2h/g) or sqrt of (2h/g).

where h stands for the height of hole in tank shell from the ground level.

This equation is true when the body is free falling with zero initial velocity. However, my question is whether the equation is valid when we are considering a liquid ejecting from the hole (which will definitely have initial velocity due to head of remaining liquid in the tank)?

Thanks in advance.
 
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Will a horizontal initial velocity matter?
 
Hi Doc Al,

Thanks for the reply. You have infact echoed my concern too. I think it matters. But when the textbook does not account for it, I am confused.

To give a clearer picture, the objective of the problem is to determine horizontal distance 'S' by which the liquid will be thrown from the hole.

In the textbook, once the time 't' is found out, they use this value of 't' in the following equation to determine 'S':

S=v*t where v is the velocity of the liquid at the hole (this velocity is determined using the energy conservation equation)

I was trying to analyse the same condition using another example. If in Case 1 a bullet is fired from a gun and in Case 2 a similar bullet is dropped from the same height of the gun, both at the same time, will both bullets reach ground at same time? I don't think so...but I can't prove it.

Best
 
ProgScience said:
I was trying to analyse the same condition using another example. If in Case 1 a bullet is fired from a gun and in Case 2 a similar bullet is dropped from the same height of the gun, both at the same time, will both bullets reach ground at same time? I don't think so...but I can't prove it.
Realize that you can treat vertical and horizontal motions completely independently. What's the equation for vertical position as a function of time for a projectile? Does the horizontal motion matter?
 
Hi Doc Al,

thanks for the thoughts. I visited the following website: http://electron9.phys.utk.edu/phys135d/modules/m3/Projectile%20motion.htm

It says that we can treat motion in two dimensions.

Vx=V0x and Vy=Vy0-gt

and

x = Vx0 t and y = Vy0t - 1/2 g t^2

therefore

t = sqrt(2y/g)

With this case, it can be concluded that both the bullets must reach ground at same time.

Am I correct?.

Thank you very much
 
Last edited by a moderator:
Yes, you are correct. The time it takes for an object to reach the ground depends only on its initial vertical speed (and distance from the ground, of course). Horizontal speed doesn't matter. The two bullets will hit the ground at the same time. (Ignoring complications of air resistance, of course.)
 
Great. Thanks :)
 

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