A helicopter traveling upward at 69 m/s drops a package from a height of 500 meters. To determine the time it takes for the package to hit the ground, the equation of motion X = 1/2 at² + Vt is utilized, where 'a' is the acceleration due to gravity (9.8 m/s²), 'V' is the initial velocity (69 m/s), and 't' is the time in seconds. The total time includes the time taken for the package to ascend before it starts descending and the time taken to fall the total distance to the ground. The final calculation results in a total time of approximately 8 seconds.
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SunKissedGal1 said:Homework Statement
A hellicopter traveling upward at 69 m/s drops a package from a height of 500 meters. To the nearest second how long does it take to hit the ground?
Homework Equations
possibly displacement??
v= 69
x=500
a=9.8
t=??
The Attempt at a Solution
do i use
X=1/2 at^2 +Vt ??
SunKissedGal1 said:Homework Statement
A hellicopter traveling upward at 69 m/s drops a package from a height of 500 meters. To the nearest second how long does it take to hit the ground?
Homework Equations
possibly displacement??
v= 69
x=500
a=9.8
t=??
The Attempt at a Solution
do i use
X=1/2 at^2 +Vt ??