Time of oscillation of a pendulum

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SUMMARY

The discussion centers on calculating the period of oscillation for a V-shaped pendulum with legs of length L and an angle of 120 degrees between them. The correct moment of inertia (I) for the V shape around the pivot point is established as I = (M * L^2) / 3, and the center of mass (R) is located at a distance of L/4 from the pivot. The final formula for the period of oscillation (T) is T = 2π√(I / (MgR)), which simplifies to T = 2π√((L^2) / (3g(L/4))). The discussion highlights the importance of correctly identifying the pivot point and the moment of inertia in such calculations.

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  • Basic trigonometry for angle measurements
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diredragon
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Homework Statement


A rigib poll of length 2L is made into a V shape so that each leg has length L. What is the period of oscillation for small angle. The angle between the legs is 120 degrees

Homework Equations


3. The Attempt at a Solution [/B]
I tried to calculate the period by imagining a rigid poll that would take the originals place. Since the length of one leg is L, the poll which would take the place is located in the middle and of length ##L/2## since its 30,60,90 triangle, Moment of inertia is ##I=\frac{M(L/2)^2}{3}## and that nakes the period ##T=6.28*\sqrt{\frac{I}{Mg(L/2)}}## and that just doesn't seem right? What do you think?
 
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You have to calculate the moment of inertia I of the V shape body around the point at the vertex of V (which I suppose is the pivot point). I believe it will be ##I=2M\frac{L^2}{3}##.Also you need to find the center of mass of the V shape body. I believe it will be at distance ##R=\frac{L}{4}## from the pivot point. Then the period will be

##T=2\pi\sqrt\frac{I}{MgR}## where R is the distance of the center of mass from the pivot point (the vertex of V).
 
Delta² said:
You have to calculate the moment of inertia I of the V shape body around the point at the vertex of V (which I suppose is the pivot point). I believe it will be ##I=2M\frac{L^2}{3}##.Also you need to find the center of mass of the V shape body. I believe it will be at distance ##R=\frac{L}{4}## from the pivot point. Then the period will be

##T=2\pi\sqrt\frac{I}{MgR}## where R is the distance of the center of mass from the pivot point (the vertex of V).
That's rather too much assistance straight up. Better would have been to leave it as
"You have to calculate the moment of inertia I of the V shape body around the point at the vertex of V (which I suppose is the pivot point).. Also you need to find the center of mass of the V shape body. "

Anyway, your expression for I is wrong.
 
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haruspex said:
That's rather too much assistance straight up. Better would have been to leave it as
"You have to calculate the moment of inertia I of the V shape body around the point at the vertex of V (which I suppose is the pivot point).. Also you need to find the center of mass of the V shape body. "

Anyway, your expression for I is wrong.

Sorry where I am wrong, the body is originally 2L and each V side has L length. Moment of intertia is aroung the peak of V not around the c.o.m.

Ok I see now the factor of 2 should be omitted.
 
Last edited:
Delta² said:
Ok I see now the factor of 2 should be omitted
Right.
 

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