Time required for falling objects speed to double

In summary, an eagle drops a fish while flying horizontally at 7.6 m/s. The fish's total speed is determined by its vertical and horizontal components. To find the total speed, use the formula √(x^2 + y^2). The question asks how much time passes before the fish's speed doubles and how much additional time would be required for the speed to double again.
  • #1
bigbobby
2
0
An eagle is flying horizontally at 7.6 m/s with a fish in its claws. It accidentally drops the fish.
(a) How much time passes before the fish's speed doubles?
(b) How much additional time would be required for the fish's speed to double again?



Maybe someone else will understand this better than I am. There is no acceleration in the x direction, so they must be talking about the y direction. But if his initial y velocity was 0 (he is flying horizontally) then you can't double 0 ...



Thanks for any help.
 
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  • #2
No, the question is talking about the total speed, both vertical and horizontal. Do you know how to find total speed given vertical & horizontal speed?
 
  • #3
Is it √(x^2 + y^2)

I'm still not quite sure how to find the vertical component though?

Thanks for your reply.
 
  • #4
Yes. The vertical component is just gt, since gravity adds 9.8 m/s to the vertical speed every second.
 

1. How does the mass of an object affect the time required for its speed to double when falling?

The mass of an object has no effect on the time required for its speed to double when falling. All objects, regardless of their mass, will take the same amount of time to double their speed when falling due to gravity.

2. Does air resistance affect the time required for an object's speed to double when falling?

Yes, air resistance can affect the time required for an object's speed to double when falling. Objects with larger surface areas or less aerodynamic shapes will experience more air resistance, causing them to take longer to double their speed when falling.

3. How does the height at which an object is dropped affect the time required for its speed to double when falling?

The height at which an object is dropped has no effect on the time required for its speed to double when falling. As long as there is no air resistance, all objects will take the same amount of time to double their speed regardless of the height from which they are dropped.

4. What is the acceleration due to gravity and how does it relate to the time required for an object's speed to double when falling?

The acceleration due to gravity is a constant value of 9.8 meters per second squared and it relates to the time required for an object's speed to double when falling through the equation t = √(2h/g), where t is the time, h is the height, and g is the acceleration due to gravity.

5. Can the time required for an object's speed to double when falling be calculated without knowing its initial speed?

Yes, the time required for an object's speed to double when falling can be calculated using the equation t = √(2h/g) even without knowing its initial speed. This is because the equation takes into account the acceleration due to gravity and the height from which the object is dropped, which are the only factors that affect the time required for the object's speed to double.

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