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Time taken to charge capacitor to 2/3 V in

  1. May 17, 2012 #1
    1. The problem statement, all variables and given/known data
    C= 0.047 micro farads
    R= 2.2K
    using the formula given, calcultae the time taken to charge the capacitor to 2/3 V in.


    2. Relevant equations

    Vc = Vin * (1-e^-t/rc)

    3. The attempt at a solution

    rc= 2.2E3 * 0.047 E-6 = 1.034E-4 seconds ( 1 time constant , 63% of vin )

    i cant figure out figure out after that, i know 1 time constant is 63% and 2/3 is slightly higher than that around 67% of vin but how do i work out the time taken to reach that?
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. May 17, 2012 #2

    gneill

    User Avatar

    Staff: Mentor

    You should be able to solve the equation for t.
     
  4. May 17, 2012 #3
    t = -rc* ln(1-vc/vn)

    got it thanks
     
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