Time taken to charge capacitor to 2/3 V in

AI Thread Summary
To calculate the time taken to charge a capacitor to 2/3 of the voltage, the relevant formula is Vc = Vin * (1 - e^(-t/RC)). Given a capacitance of 0.047 microfarads and a resistance of 2.2K ohms, the time constant (RC) is calculated as 1.034E-4 seconds. To find the time for 2/3 voltage, the equation t = -RC * ln(1 - Vc/Vin) can be used, where Vc is 2/3 of Vin. The discussion concludes with a confirmation that the solution was understood.
mogley76
Messages
17
Reaction score
0

Homework Statement


C= 0.047 micro farads
R= 2.2K
using the formula given, calcultae the time taken to charge the capacitor to 2/3 V in.


Homework Equations



Vc = Vin * (1-e^-t/rc)

The Attempt at a Solution



rc= 2.2E3 * 0.047 E-6 = 1.034E-4 seconds ( 1 time constant , 63% of vin )

i can't figure out figure out after that, i know 1 time constant is 63% and 2/3 is slightly higher than that around 67% of vin but how do i work out the time taken to reach that?
 
Physics news on Phys.org
You should be able to solve the equation for t.
 
t = -rc* ln(1-vc/vn)

got it thanks
 
Thread 'Voltmeter readings for this circuit with switches'

Thread 'Voltmeter readings for this circuit with switches'

TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
View full post »
Thread 'Correct statement about a reservoir with an outlet pipe'

Thread 'Correct statement about a reservoir with an outlet pipe'

The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
View full post »

Similar threads

TIme needed for a capacitor to reach a fraction of its final charge
Replies
2
Views
2K
Finding Current in Resistors & Charge of Capacitor
Replies
4
Views
2K
Capacitor Questions Charging and Discharging
Replies
4
Views
3K
Ranking charge stored on three capacitors by a battery
Replies
6
Views
3K
What does "Fully Charged Capacitor" mean?
Replies
6
Views
3K
Finding the time for charging Voltage
Replies
9
Views
2K
Time for capacitor charging in RLC circuit.
Replies
3
Views
3K
Capacitor circuit time constant problem
Replies
2
Views
2K
A Capacitor with initial charge
Replies
3
Views
3K
Maximum charge on the plates of a capacitor
Replies
2
Views
2K

Hot Threads

Recent Insights

Back
Top