- #1
petern
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A pendulum clock that works perfectly on Earth is taken to the moon where g = 1.63 m/s^2. If the clock is started at 12:00 A.M., what will it read on the moon 24 Earth hours?
The equation you would probably use is T = 2(pi)(sq. root of m/k)
Can someone get me started?
The equation you would probably use is T = 2(pi)(sq. root of m/k)
Can someone get me started?
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