What are D1 and D2, and how do you get the second equation from the first?robax25 said:T1/T2=√(D1/D2)
=√((Gmr^2/9,81)/D1)
What is l (lower-case L)? What is g?robax25 said:D means g . If you divideT1/T2=2*π√l1/g / 2*π√l2/g. the you get the equation
L is the length of the pendulum and g is the Gravitational costantNascentOxygen said:What is l (lower-case L)? What is g?
yes, G differs from Earth to Jupiter's moon Io. For earth, it is 9.81m/s^2... and Io moon is not mentioned. so we need to use gravitational formula to solve itNascentOxygen said:It's one pendulum clock that gets transported to Io, so how can there be two different pendulum lengths?
Usually G is the gravitational constant symbol. What numerical value are you using for lower-case g here?
I have clarified the problem statement here, to present it as I believe would have been intended.robax25 said:Homework Statement
you are taking your pendulum clock with you to a visit of the Jupiter moon Io(radious 3643.2Km, mass 8.94X10^22 kg. calculate the duration of a full Oscillation. On the Earth's surface this oscillation time was 1s
i mean that.NascentOxygen said:I have clarified the problem statement here, to present it as I believe would have been intended.
No, I do not have the equation. I am confused.NascentOxygen said:So you have a final equation for TIo that involves the mass of Io?
NascentOxygen said:Where's the confusion?
If you divideT1/T2=2*π√l/g1 / 2*π√l/g2. the you get the equation l= radious of the Pendulum and g is the gravitational constant.NascentOxygen said:You'll need to show the working you followed in deriving that equation, by starting with something that you know to be right.
The period of a pendulum on Jupiter's moon Io would depend on several factors, such as the length of the pendulum, the strength of gravity on Io, and the amplitude of the pendulum's swing. However, assuming a standard pendulum length and amplitude, the period would be approximately 45 minutes.
The period of a pendulum on Io would be significantly shorter than on Earth due to Io's stronger gravitational pull. On Earth, a pendulum with a length of 1 meter has a period of approximately 2 seconds, while on Io, it would have a period of about 45 minutes.
Yes, the period of a pendulum on Io would vary at different locations on the moon. This is because the strength of gravity is not constant on Io, as it has varying topography and mass distribution.
Yes, the period of a pendulum on Io may also be affected by the moon's orbital eccentricity, which could cause slight variations in gravity at different points in its orbit.
The period of a pendulum on Io would not be significantly affected by the moon's volcanic activity. Although volcanic eruptions may cause temporary disturbances in Io's gravity, these effects would not be significant enough to alter the period of a pendulum in a noticeable way.