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Period of a pendulum: [tex]T = 2\pi\sqrt{\frac{I}{mgh}}[/tex]

I: inertia

m: mass

g: accelleration due to gravity, 9.80665

h: distance from the pivot to the center of gravity

I am actually only interested in the fall of the pendulum, from horizontal to vertical. I have figured out I, m, g and h for my device (it uses ball bearings, so friction can probably be ignored) and calculated the time to fall by quartering the period. The answer is close to my observations, but I need it exact, to within +/- about ten microseconds.

Can someone tell me if I am doing this right? If not, then what is the formula for the fall of a pendulum from the horizontal?