To calculate torque on a supported beam

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To calculate the torque on a supported beam, the discussion focuses on determining the torque L after applying forces F1 and F2. The user has already established the center of gravity and weight equations, but struggles with setting up the equation for torque. It is noted that taking moments about a specific axis can simplify the calculations by excluding certain unknown forces. Ultimately, the key to solving the problem lies in correctly identifying the axis for moment calculations. The conversation concludes with the user gaining clarity on the approach needed to find the torque.
gnits
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Homework Statement
To calculate torque on a supported beam
Relevant Equations
equate forces and torques
Could I please ask for help with the last part of the following question?

q.JPG


I have the first two parts done, answers are:

Distance of COG from A = a(1+n)/n

and W1 = W(1+n)/3

I can't see how to go about the last part. Here's my diagram for the system prior to the torque L being added:

d.png

In this situation we have (are told) F1 = F2 = F say, and so W1 + W + nW = 2F and so as we know W1 in terms of W and n we have F = 2W(n+1)/3 and we are told that after torque L is applied then this increases by 1.5 times, so now F1 = W(n+1) and so F2 = W(n+1)/3. As F1 has increased then we know that L is counter-clockwise.

Can't see though what equation to set up to calculate the L which would lead to this value for F1.

Thanks for any help,
Mitch.
 
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Of all the forces acting on the beam after L is applied, which is the one that you neither know nor care about? What axis can you take moments about to avoid involving that force?
 
haruspex said:
Of all the forces acting on the beam after L is applied, which is the one that you neither know nor care about? What axis can you take moments about to avoid involving that force?

Thanks very much. That helped me to see it. Moments about Q.

Mitch.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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