To find the midpoint of a line AB,with the given points A and B

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Discussion Overview

The discussion revolves around finding the midpoint of a line segment defined by two points A and B in three-dimensional space, and subsequently determining the unit vector extending from the origin toward this midpoint. The scope includes homework-related problem-solving and mathematical reasoning.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • One participant calculates the direction vector to AB as (-6,-3,3) and proposes that the direction vector to its midpoint is (-3,-1.5,1.5), leading to a unit vector calculation.
  • Another participant expresses doubt about the initial approach and suggests recalculating the midpoint of line AB.
  • A participant acknowledges a mistake with the midpoint formula and proposes a new midpoint of (1,1.5,3.5), seeking confirmation of its correctness.
  • A later reply confirms that the proposed midpoint (1,1.5,3.5) is indeed correct.

Areas of Agreement / Disagreement

There is a general agreement on the correctness of the midpoint (1,1.5,3.5) after initial confusion regarding the midpoint formula. However, there remains uncertainty about the initial calculations and methods used to arrive at the midpoint and unit vector.

Contextual Notes

Participants have not fully resolved the initial steps leading to the midpoint calculation, and there may be dependencies on definitions of vectors and formulas that are not explicitly stated.

Who May Find This Useful

Students or individuals interested in vector mathematics, particularly in the context of geometry and three-dimensional space, may find this discussion relevant.

Abel I Daniel
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Homework Statement


*)Given two points A=(4,3,2) and B=(-2,0,5).Find the unit vector extending from origin toward the midpoint of line AB


Homework Equations





The Attempt at a Solution



Direction vector to AB=(-6,-3,3) and hence direction vector to its midpoint is (-3,-1.5,1.5)
So unit vector in the direction of (-3,-1.5,1.5) is (-3i-1.5j+1.5k)/√(9+2.25+2.25).

Is this the way to do it??
 
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I doubt that you have begun this correctly, but my maths is very rusty.

Perhaps you should take another look at it by first calculating the midpoint of line AB.
 
Abel I Daniel said:

Homework Statement


*)Given two points A=(4,3,2) and B=(-2,0,5).Find the unit vector extending from origin toward the midpoint of line AB


Homework Equations





The Attempt at a Solution



Direction vector to AB=(-6,-3,3) and hence direction vector to its midpoint is (-3,-1.5,1.5)
So unit vector in the direction of (-3,-1.5,1.5) is (-3i-1.5j+1.5k)/√(9+2.25+2.25).

Is this the way to do it??

No. Look up the formula for the mid-point between two points.
 
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oh,i got wrong with the midpoint formula..so now the midpoint is (1,1.5,3.5).is it correct??
 
Abel I Daniel said:
oh,i got wrong with the midpoint formula..so now the midpoint is (1,1.5,3.5).is it correct??
That is the midpoint, yes.
 
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