- #1

BrownBoi7

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Tom and Jerry both push on the 3 m diameter merry-go-round shown in the figure attached.

(a) If Tom pushes with a force of 40 N and Jerry pushes with a force of 35.2 N, what is the net torque on the merry-go-round?

(b) What is the net torque if Jerry reverses the direction by 180 degrees without changing the magnitude of his force?

My attempt:

FT = Force exerted by Tom = 40 N

FJ = Force exerted by Jerry = 35.2 N

T = Torque = RF sinΘ

TT = 1.5 m * 40 N * sin 60 = 1.5 m * 40 N * -0.304 = -18.28 Nm

TJ = 1.5 m * 35.2 N * sin 80 = 1.5 m * 35.2 N * -0.993= --52.43 Nm

(a) Net T= -18.28 Nm + (- 52.43 Nm) = -70.71 Nm

(b) When Jerry reverses,

Net T = -18.28 Nm - (-52.43 Nm) = 34.15 Nm

My answers didn't match my professor's answers. I believe I went about it the right way. Could somebody please point out where I messed up?

Thanks!

(a) If Tom pushes with a force of 40 N and Jerry pushes with a force of 35.2 N, what is the net torque on the merry-go-round?

(b) What is the net torque if Jerry reverses the direction by 180 degrees without changing the magnitude of his force?

My attempt:

FT = Force exerted by Tom = 40 N

FJ = Force exerted by Jerry = 35.2 N

T = Torque = RF sinΘ

TT = 1.5 m * 40 N * sin 60 = 1.5 m * 40 N * -0.304 = -18.28 Nm

TJ = 1.5 m * 35.2 N * sin 80 = 1.5 m * 35.2 N * -0.993= --52.43 Nm

(a) Net T= -18.28 Nm + (- 52.43 Nm) = -70.71 Nm

(b) When Jerry reverses,

Net T = -18.28 Nm - (-52.43 Nm) = 34.15 Nm

My answers didn't match my professor's answers. I believe I went about it the right way. Could somebody please point out where I messed up?

Thanks!