Torque and angular acceleration of two discs

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Homework Statement



2nv7d7a.jpg


Homework Equations



Ʃ[itex]\tau[/itex] = I[itex]\alpha[/itex]
ƩF = ma

The Attempt at a Solution



I was able to calculate A and B which I am confident is correct..

2r5dd1x.jpg


for part C is what I'm having trouble with. Since both disks are fixed together, does that mean they share the same angular acceleration? if so I think the way to go about this is I apply the equation

Ʃ[itex]\tau[/itex] = I[itex]\alpha[/itex]

where it will be T1R1 - T2R2 = I[itex]\alpha[/itex] and I just solve for alpha.

but since they are now accelerating.. doesn't that change each tension to be t = mg + ma? instead of just t = mg ? which then makes it much more difficult to solve..

unless if the tensions are just mg then it will be fairly easy to solve since I can find the alpha of the rotating system then just apply the equation

a = [itex]\alpha[/itex]R

and calculate the a for each, and from there I will be able to find the tensions in each rope.
 
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Since both disks are fixed together, does that mean they share the same angular acceleration?
Yes - that is what "fixed together" means. You needed to assume this to do (a) and (b).

since they are now accelerating.. doesn't that change each tension to be t = mg + ma?
Use the free-body diagram to inform you of the tensions. Don't anticipate.