Torque and power in a geared sytem

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SUMMARY

The discussion centers on calculating power and torque in a geared system, specifically focusing on the relationship between input power and output power in shaft B. The user employs the equation p = T * 2π * f, where T represents torque and f represents frequency in rotations per second. The user concludes that the power in shaft B is 95% of the input power, leading to the calculation of maximum torque in shaft B at 579.07 Nm when the system operates at 2444 RPM. This approach confirms the understanding of power transfer in geared systems.

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Homework Statement


The problem is attached, I am only looking for guidance on a, I am most probably just completely over complicating this.


Homework Equations


p=T.2(pi).f

t= torque
f=frequency/rot/sec



The Attempt at a Solution


im just stuck on wether the power in shaft b is simply 95percent of the systems input power, or wether i calculate the torque in shaft a, and then calculate the power in b and subtract a 5 percent from that. Thats what i tried however I got a power higher then the input. Please help.
 

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p.s. thanks in advance.
 
so I am leaning towards the idea that power is simply .95 percent of the power supplied, meaning that the angular velocity and the torque are obviously different. am i on the right track of understanding this?
 
so assuming that this is correct, i then attempted b.
it asks for max torque in shaft b, max torque occurs at max power.
max power occurs when 2444 rpm.
40/208 = .1923 rotations to every one of the small gear
x by 2444
/60
= 7.8 rots/sec of the large gear.
so
p=T.2(pi).f
28.5x10^3=T.2(pi).7.833
T=579.07 nm

does this look correct?

thanks for input.
 

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