What Changes When You Reduce Car Wheel Size by 4%?

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SUMMARY

Reducing car wheel size by 4% from 25 inches to 24 inches does not increase torque; the torque remains constant at 100 Nm. However, the tractive effort increases due to a smaller dynamic rolling radius, calculated using the formula tractive effort = Torque/tyre radius. With a 25-inch tyre, the tractive effort is 314 N, while with a 24-inch tyre, it rises to 328.08 N. This increase in tractive effort can enhance a vehicle's ability to climb gradients.

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Nick666
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So let's assume I have 100 Nm at the wheel of a car, with a wheel size of 25 in diameter

If I put wheels that are 24 in diameter, so 4% smaller, what exactly will change ? Will I have 4% more torque ?
 
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Waaat.

You'll have exactly the same amount of torque. Something will change at the contact patch through.
 
Isnt there some formula that might be applied here ? ... F = T*r ? Doesnt a change in wheel size of a car act like a gear change ?
 
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Ohhh...its F=T/r ... I get it now.
 
If F is the ground force on the wheel then T- F.r = IG
 
Also your rpm changes. The circumference (pi*D) is less on the smaller diameter.
 
no you won't have more torque .. torque is a function of gear ratios at wheel torque = engine torque*gear ratios*differential ratio
So when you are considering change in tyre dimensions assume it constant. so for changing wheel selection following things will occur.
in this case your tractive force will increase..
tractive effort= Torque/tyre radius (dynamic rolling radius)
say you have 100Nm of torque which is constant
now you used 25inch tyre= radius=0.3175m
so tractive effort = 100/.3175=314N

Now you used 24inch dia tyre=radius=.3048m
so tractive effort = 328.08N

so basically your tractive effort increases which can help you to climb gradients..
you can calculate percentages.
 

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